Iodine is a chemical element which has a symbol I. The atomic number of Iodine is 53. It is the heaviest of the stable halogens. It exists as a purple-black, lustrous, non-metallic solid at favourable conditions which readily sublimes to form a violet gas.
The elemental form of Iodine was discovered by Bernard Courtois, a French chemist in 1811. Iodine was named two years later by Joseph-Louis Gay-Lussac from this property. It is found in many oxidation states which includes iodide and iodate and many other various periodate anions.
Iodine is the least abundant of the stable halogens and also the sixty-first most abundant element. Today we are going to give you all the information related to electron configuration of the Iodine.
Iodine Number of Valence Electrons
Iodine has seven Valence Electron.
What is The Electron Configuration of Iodine
There are 53 electrons in iodine that occupy the respective orbitals as given below;
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁵
As 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ is the electronic configuration of the previous noble gas Krypton, Kr, so we write it like
[Kr] 5s² 4d¹⁰ 5p⁵
You can also see the image below
How Many Valence Electrons Does Iodine Have
There are 7 valence electrons with Iodine.